<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN"> <HTML><HEAD> <META http-equiv=Content-Type content="text/html; charset=us-ascii"> <META content="MSHTML 6.00.2900.2963" name=GENERATOR></HEAD> <BODY id=role_body style="FONT-SIZE: 10pt; COLOR: #000000; FONT-FAMILY: Arial" bottomMargin=7 leftMargin=7 topMargin=7 rightMargin=7> <DIV dir=ltr align=left><SPAN class=100443115-30082006>I have some thoughts on Scott's back of the envelop calculation below. It seems (to me)  plausible that a Grotto marathon removes water from the interstices below Giant and its associated geysers. Because water is an effective absorber of heat (that's why it's used in car radiators) and air isn't, the result is that the rocks around the interstices will increase significantly in temperature. (Think of what happens to your car when a radiator hose breaks.) Thus, when water fills in the voids after Grotto ends, there is more energy available for the recovery hot period and/or a Giant eruption.</SPAN></DIV> <DIV dir=ltr align=left><SPAN class=100443115-30082006></SPAN> </DIV> <DIV dir=ltr align=left><SPAN class=100443115-30082006>Now, I have a question: Is the data available to do a linear regression on the length of Grotto marathons and the time from Grotto's shut down to the recovery hot period?</SPAN></DIV> <DIV dir=ltr align=left><SPAN class=100443115-30082006></SPAN> </DIV> <DIV dir=ltr align=left><SPAN class=100443115-30082006></SPAN> </DIV> <DIV dir=ltr align=left><SPAN class=100443115-30082006>Allan Moose</SPAN></DIV> <DIV dir=ltr align=left><SPAN class=100443115-30082006></SPAN> </DIV> <DIV dir=ltr align=left><SPAN class=100443115-30082006></SPAN> </DIV> <DIV dir=ltr align=left><SPAN class=100443115-30082006>"Science is just organized curiosity"</SPAN></DIV> <DIV dir=ltr align=left><SPAN class=100443115-30082006>(Donald Kroodsma)</SPAN></DIV> <DIV dir=ltr align=left><SPAN class=100443115-30082006>  </SPAN></DIV><BR> <DIV class=OutlookMessageHeader lang=en-us dir=ltr align=left> <HR tabIndex=-1> <FONT face=Tahoma><B>From:</B> geysers-bounces@wwc.edu [mailto:geysers-bounces@wwc.edu] <B>On Behalf Of </B>TSBryan@aol.com<BR><B>Sent:</B> Monday, August 28, 2006 4:04 PM<BR><B>To:</B> geysers@wwc.edu<BR><B>Subject:</B> [Geysers] Grotto discharge<BR></FONT><BR></DIV> <DIV></DIV><FONT id=role_document face=Arial> <DIV>An idle thought that likely is nothing more than that. But the other day Ralph Taylor wondered about the discharge volume of Grotto Geyser. Looking at Marler's Inventory, Marler cites a value of 670 gallons per minute -- that strikes me as being precise enough as to have been determined by actual measurement.</DIV> <DIV> </DIV> <DIV>OK, so... do some multiplication and you find that a 33-34 hour long Grotto marathon -- about as long as they ever can be -- will discharge something around 1,000,000 gallons. And of course, the commonly-cited value of discharge during a Giant eruption is 1,000,000 gallons.</DIV> <DIV> </DIV> <DIV>So, Grotto has a long marathon, discharging 1,000,000 gallons from the entire Grotto-Giant system. That volume is regained during the hours leading up to Giant's recovery hot period, which as we know frequently results in a Giant eruption. So...</DIV> <DIV> </DIV> <DIV> </DIV> <DIV>... now you carry the thought onward.</DIV> <DIV> </DIV> <DIV>Scott Bryan</DIV></FONT></BODY></HTML>